9x^2-54x-19=0

Solution for 9x^2-54x-19=0 equation:

9x^2-54x-19=0

a = 9; b = -54; c = -19;
Δ = b2-4ac
Δ = -542-4·9·(-19)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-60}{2*9}=\frac{-6}{18}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+60}{2*9}=\frac{114}{18}
=6+1/3
$